In article <650sjbF2cc93pU1@mid.individual.net>,
"Reality_Check©" wrote:
> "Larry" wrote in message
> news:x-B01332.01562527032008@earthlink.vsrv-sjc.supernews.net...
> > In article <650pveF2dcsonU1@mid.individual.net>,
> > "Reality_Check©" wrote:
> >
> >> "Larry" wrote in message
> >> news:x-EDB477.22171526032008@earthlink.vsrv-sjc.supernews.net...
> >> >>
> >> >> Possession of half a gram (not much) is a class D felony, P.L. 220.06.
> >> >
> >> > If you look at the statute closely, unlike the other weight-based
> >> > cocaine charges, this must be 500 milligrams of PURE cocaine. Since
> >> > street-level cocaine is far from pure (generally, anywhere from
> >> > 40-80%),
> >> > generally people are in possession of far more than a gram for this
> >> > statute to actually apply.
> >>
> >> More Larry the Liar bullshit.
> >>
> >> If a 1/2 gram of PURE is the standard, and by your own assertions
> >> "street-level"
> >> cocaine (is that P Diddy level, Martha Stewart or Britney Spears level?)
> >> is
> >> 40-80% pure,
> >> then possession of as little as 6.25 TENTHS of a GRAM of street level
> >> cocaine qualifies
> >> as a felony.
> >
> > How is 40% to 80% of 6.25 tenths of a gram over 500 milligrams? Your
> > math, like your thinking, is backwards.
>
> That about sums up the level of your "expertise".
Lets see if you can follow:
1) one tenth of a gram is .1 grams, or 100 milligrams.
2) 6.25 tenths, then, is .625 grams, or 625 milligrams.
3) I said 40% to 80%. So lets look at both of those numbers:
3a) 40% of 625 milligrams is 250 milligrams.
3b) 80% of 625 milligrams is 500 milligrams.
So I ask again - how is How is 40% to 80% of 6.25 tenths of a gram over
500 milligrams? |